Joshua Peek
94 B
94 B
[ P(E) = {n \choose k} p^k (1-p)^{ n-k} ]
The Pythagorean theorem is ( a^2 + b^2 = c^2 ).
[ P(E) = {n \choose k} p^k (1-p)^{ n-k} ]
The Pythagorean theorem is ( a^2 + b^2 = c^2 ).